As per given a=72, d=-2, l=40
Therefore, l=a+(n-1)d
40=72+(n-1)(-2)
=72-2n +2
2n=34
n=17
Now,the required sum of n terms,
=n/2(a+l)
=17/2(72+40)
=17/2*112
=17*56
=952
As per given a=72, d=-2, l=40
Therefore, l=a+(n-1)d
40=72+(n-1)(-2)
=72-2n +2
2n=34
n=17
Now,the required sum of n terms,
=n/2(a+l)
=17/2(72+40)
=17/2*112
=17*56
=952